Evan Tang Elder Moderator | Fri Jul 17, 2020 | 10:54 AM | Likes: 2 

How to Make Letters Horizontal, Vertical, Backwards, and Intersect when Coding a Word Search Game in Python

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Do you want to learn how to make letters horizontal, vertical, backwards, and intersect when coding a word search game in Python? If you said yes, than you should read this article, because it will teach you how. First, how to make words horizontal and how to make those horizontal words backwards. To do this, you first need to make a function. You then need to put things inside the function. Here is an example. def add_word(word,arr):# make a function     col=random.choice(lst)#chooses a random location in the columns for the word to be placed     lst.remove(col)# removes that place so another word does not get placed there     row=random.randint(0,15-len(word))# chooses a random row for the word to be placed, however the length of the word must fit into the row and cannot go over the limit     rand_num = random.randint(0,1)# 0 means that the word is backwards, 1 means that is forward     if rand_num == 0: # if the random number is 0, then you make the word backwards         word1 = word[::-1]# [::-1] makes words reversed     else: # if it is not 0, then keep it the same         word1 = word     for i in range(0,len(word1)): # printing the i         arr[col,row+i]=lett2num[word1[i]] Next I will tell you how to add the vertical words, make it backwards, and make them cross with the horizontal words. Adding a vertical word is almost the same as adding a horizontal one. The difference is that vertical ones are basically the opposite of horizontal ones. Here is an example. def add_word1(word,arr): # make a function     row=random.choice(lst)#chooses a random location in the rows for the word to be placed     lst.remove(row)# removes that place so another word does not get placed there     col=random.randint(0,15-len(word))# chooses a random column for the word to be placed, however the length of the word must fit into the row and cannot go over the limit     addvword = True # make a new variable for adding vertical word. This is so vertical words and horizontal ones can cross     count = 0 # set count to 0     rand_num = random.randint(0,1)# 0 means that the word is backwards, 1 means that is forward     if rand_num == 0: if the random number is 0, then you make the word backwards         word1 = word[::-1]# [::-1] makes words reversed     else:# if it is not 0, then keep it the same         word1 = word     for i in range(0,len(word1)):# printing the i         arr[col+i,row]=lett2num[word1[i]]     for i in range(0,len(word1)):         if arr[col+i,row]!=0:# if the adding vertical word space is taken...             addvword = False #you cannot add that vertical word there             if arr[col+i,row] == lett2num[word1[i]]:# if the array is equal to the word1 letter...                 count +=1 # add one to the count             else: # if that is not true...                 count = 0# keep count at 0     if count != 0: # if the count is not zero...         for i in range(0,len(word1)):             arr[col+i,row]=lett2num[word1[i]] # the array is equal to the word1 letter     elif addvword: # if that is not true, addvword is equal to true         for i in range(0,len(word1)):             arr[col+i,row]=lett2num[word1[i]]# you can cross the word with another word if the crossing letter is the same By now, you should have a better understanding of how to make letters horizontal, vertical, backwards, and intersect when coding a word search game in Python.