How to Make Diagonal Words and Making them Backwards Using Python
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Do you know the algorithm to make a crossword puzzle using Python? If you do not know how, then you should read this article because it will teach you how. We will make two arrays one of them has the correct answers while the other one has the letter O to replace the words. Here is the code. added_words_count = 0# make a variable equal to zero def add_word(word,arr): #this function adds the horizontal words to the cross word global added_words_count#global that variable that was made row=random.choice(lst)#take a random row to put the word in lst.remove(row)# remove it so it does not repeat col=random.randint(0,15-len(word))# choose a random column to put the word in addhword = True#set this variable to true for adding horizontal words count = 0#set count to zero rand_num = random.randint(0,1)# randomly choosing 1 or 0 to decide if the word goes from right to left or left to right. if rand_num == 0:if the random number is zero word1 = word[::-1]# make it backwards else: # if the random number is not zero word1 = word# keep it the same for i in range(0,len(word1)):# print i arr[row,col+i]=lett2num[word1[i]] added_words_count += 1 #add one to the added_words_count variable print('added horizontal')# print added horizontal to know how many words you added were horizontal def add_word1(word,arr):# this function is for adding vertical words global added_words_count# global the added_words_count variable addvword = True# set adding vertical words to true rand_num = random.randint(0,1)# randomly choosing 1 or 0 to decide if the word goes from right to left or left to right. if rand_num == 0:if the random number is zero word1 = word[::-1]# make it backwards else: # if the random number is not zero word1 = word# keep it the same def adding_v_word():# make another function for adding completely_empty = True# set the completely empty variable to true col=random.choice(lst)# lst.remove(col) row=random.randint(0,15-len(word))# choose a random row to put the word in ready = False# set the variable ready to false for i in range(0,len(word1)):print i if arr[row+i,col] != 0:# if it is not equal to zero completely_empty = False# the completely empty variable is equal to false addvword = False# also, adding a vertical word would be false # if the letter in this square is the same as the one we're adding if arr[row+i,col] == lett2num[word1[i]]:# if it is equal addvword = True# adding vertical word is true ready = True# also ready is true else:if that is not true addvword = False # both are false ready = False break # use break method return row, col, ready, completely_empty# return the variables while True:# while that is true row, col, ready, completely_empty = adding_v_word()# those variables equal adding_v_word() if ready or completely_empty:# if ready or completely_true are true for i in range(0,len(word1)):# print i arr[row+i,col]=lett2num[word1[i]] print('just added another vertical') # print this so you know when you added a vertical word added_words_count += 1 break def display_arr(arr):# this function is for displaying the array for row in range(0,15):# for the row in the range of 0 to 15 line=""# set line to an empty string for col in range(0,15):# for the column in the range of 0 to 15 line = line + num2lett[(arr[row,col])] + " "# set line to line plus the num2lett plus an empty string print(line)# print line print()# print empty space so it is easier to see the two arrays for row in range(0,15):# for the row in the range of 0 to 15 for col in range(0,15):# for the column in the range of 0 to 15 if arr[row, col] != lett2num['X']:# if it is not equal, use the letter X arr[row, col] = lett2num['O'] # if it is equal, use the letter O for row in range(0,15):# for the row in the range of 0 to 15 line1=""# line1 equals empty string for col in range(0,15):# for the column in the range of 0 to 15 line1 = line1 + num2lett[(arr[row,col])] + " " print(line1)# print line1 print('added words', added_words_count)# print all of the parts By now you should have a better understanding of the algorithm to create a crossword game using Python.
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Liked by: Andy Tang, H2O