Evan Tang
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| Mon Aug 03, 2020 | 09:01 AM |
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Do you know the algorithm to make a crossword puzzle using Python? If you do not know how, then you should read this article because it will teach you how. We will make two arrays one of them has the correct answers while the other one has the letter O to replace the words. Here is the code.
added_words_count = 0# make a variable equal to zero
def add_word(word,arr): #this function adds the horizontal words to the cross word
global added_words_count#global that variable that was made
row=random.choice(lst)#take a random row to put the word in
lst.remove(row)# remove it so it does not repeat
col=random.randint(0,15-len(word))# choose a random column to put the word in
addhword = True#set this variable to true for adding horizontal words
count = 0#set count to zero
rand_num = random.randint(0,1)# randomly choosing 1 or 0 to decide if the word goes from right to left or left to right.
if rand_num == 0:if the random number is zero
word1 = word[::-1]# make it backwards
else: # if the random number is not zero
word1 = word# keep it the same
for i in range(0,len(word1)):# print i
arr[row,col+i]=lett2num[word1[i]]
added_words_count += 1 #add one to the added_words_count variable
print('added horizontal')# print added horizontal to know how many words you added were horizontal
def add_word1(word,arr):# this function is for adding vertical words
global added_words_count# global the added_words_count variable
addvword = True# set adding vertical words to true
rand_num = random.randint(0,1)# randomly choosing 1 or 0 to decide if the word goes from right to left or left to right.
if rand_num == 0:if the random number is zero
word1 = word[::-1]# make it backwards
else: # if the random number is not zero
word1 = word# keep it the same
def adding_v_word():# make another function for adding
completely_empty = True# set the completely empty variable to true
col=random.choice(lst)# lst.remove(col)
row=random.randint(0,15-len(word))# choose a random row to put the word in
ready = False# set the variable ready to false
for i in range(0,len(word1)):print i
if arr[row+i,col] != 0:# if it is not equal to zero
completely_empty = False# the completely empty variable is equal to false
addvword = False# also, adding a vertical word would be false
# if the letter in this square is the same as the one we're adding
if arr[row+i,col] == lett2num[word1[i]]:# if it is equal
addvword = True# adding vertical word is true
ready = True# also ready is true
else:if that is not true
addvword = False # both are false
ready = False
break # use break method
return row, col, ready, completely_empty# return the variables
while True:# while that is true
row, col, ready, completely_empty = adding_v_word()# those variables equal adding_v_word()
if ready or completely_empty:# if ready or completely_true are true
for i in range(0,len(word1)):# print i
arr[row+i,col]=lett2num[word1[i]]
print('just added another vertical') # print this so you know when you added a vertical word
added_words_count += 1
break
def display_arr(arr):# this function is for displaying the array
for row in range(0,15):# for the row in the range of 0 to 15
line=""# set line to an empty string
for col in range(0,15):# for the column in the range of 0 to 15
line = line + num2lett[(arr[row,col])] + " "# set line to line plus the num2lett plus an empty string
print(line)# print line
print()# print...
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